MCQ
Sum
\[\left\{ \left( \frac{1}{3} \right)^2 \right\}^4\] is equal to
Options
\[\left( \frac{1}{3} \right)^6\]
- \[\left( \frac{1}{3} \right)^8\]
- \[\left( \frac{1}{3} \right)^{24}\]
- \[\left( \frac{1}{3} \right)^{16}\]
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Solution
\[\left( \frac{1}{3} \right)^8\]
We have:
\[\left\{ \left( \frac{1}{3} \right)^2 \right\}^4\] `=(1/3)^(2xx4)` → ( (am)n = amxn)
`=(1/3)^8`
Concept: Powers with Negative Exponents
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