मराठी
Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

Advertisements
[object Object]
[object Object]
विषय
मुख्य विषय
अध्याय
Advertisements
Advertisements
Mathematics
< prev  5281 to 5300 of 5490  next > 

If \[\vec{a} = \hat{i} + \hat{j} + \hat{k} , \vec{b} = 4 \hat{i} - 2 \hat{j} + 3 \hat{k} \text { and } \vec{c} = \hat{i} - 2 \hat{j} + \hat{k} ,\] find a vector of magnitude 6 units which is parallel to the vector \[2 \vec{a} - \vec{b} + 3 \vec{c .}\]

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find a vector of magnitude of 5 units parallel to the resultant of the vectors \[\vec{a} = 2 \hat{i} + 3 \hat{j} - \hat{k} \text{ and } \vec{b} = \hat{i} - 2 \hat{j} +\widehat{k} .\]

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Advertisements
\[\int\limits_{- \pi/2}^{\pi/2} \sin^4 x\ dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Find a vector \[\vec{r}\] of magnitude \[3\sqrt{2}\] units which makes an angle of \[\frac{\pi}{4}\] and \[\frac{\pi}{4}\] with y and z-axes respectively. 

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

A vector \[\vec{r}\] is inclined at equal angles to the three axes. If the magnitude of \[\vec{r}\] is \[2\sqrt{3}\], find \[\vec{r}\].

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Define "zero vector".

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Evaluate the following integrals as limit of sums:

\[\int_1^3 \left( 3 x^2 + 1 \right)dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Write a vector of magnitude 12 units which makes 45° angle with X-axis, 60° angle with Y-axis and an obtuse angle with Z-axis.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find a vector in the direction of \[\overrightarrow{a} = 2 \hat{i} - \hat{j} + 2 \hat{k} ,\] which has magnitude of 6 units.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Write two different vectors having same magnitude.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Write a vector in the direction of vector \[5 \hat{i} - \hat{j} + 2 \hat{k}\] which has magnitude of 8 unit.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find a vector \[\overrightarrow{a}\] of magnitude \[5\sqrt{2}\], making an angle of \[\frac{\pi}{4}\] with x-axis, \[\frac{\pi}{2}\] with y-axis and an acute angle θ with z-axis. 

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find a vector in the direction of vector \[2 \hat{i} - 3 \hat{j} + 6 \hat{k}\] which has magnitude 21 units.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

If in a ∆ABC, A = (0, 0), B = (3, 3 \[\sqrt{3}\]), C = (−3\[\sqrt{3}\], 3), then the vector of magnitude 2 \[\sqrt{2}\] units directed along AO, where O is the circumcentre of ∆ABC is 

 

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find the distance of the point  \[2 \hat{i} - \hat{j} - 4 \hat{k}\]  from the plane  \[\vec{r} \cdot \left( 3 \hat{i}  - 4 \hat{j}  + 12 \hat{k}  \right) - 9 = 0 .\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the points \[\hat{i}  - \hat{j}  + 3 \hat{k}  \text{ and }  3 \hat{i}  + 3 \hat{j}  + 3 \hat{k} \] are equidistant from the plane \[\vec{r} \cdot \left( 5 \hat{i}  + 2 \hat{j}  - 7 \hat{k}  \right) + 9 = 0 .\]

  
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the distance of the point (2, 3, −5) from the plane x + 2y − 2z − 9 = 0.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equations of the planes parallel to the plane x + 2y − 2z + 8 = 0 that are at a distance of 2 units from the point (2, 1, 1).

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the points (1, 1, 1) and (−3, 0, 1) are equidistant from the plane 3x + 4y − 12z + 13 = 0.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined
< prev  5281 to 5300 of 5490  next > 
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×