(English Medium) ICSE Class 9 - CISCE Question Bank Solutions for Mathematics

What principal will amount to Rs. 9,856 in two years, if the rates of interest for successive years are 10% and 12% respectively ?

On a certain sum, the compound interest in 2 years amounts to Rs. 4,240. If the rate of interest for the successive years is 10% and 15% respectively, find the sum.

At what per cent per annum will Rs. 6,000 amount to Rs. 6,615 in 2 years when interest is compounded annually?

At what rate percent compound interest, does a sum of money become 1.44 times of itself in 2 years?

At what rate percent will a sum of Rs. 4,000 yield Rs.1,324 as compound interest in 3 years?

A person invests Rs5,000 for three years at a certain rate of interest compounded annually. At the end of two years this sum amounts to Rs6,272. Calculate :
(i) the rate of interest per annum.
(ii) the amount at the end of the third year.

In how many years will Rs. 7,000 amount to Rs. 9,317 at 10% per annum compound interest?

Find the time, in years, in which Rs. 4,000 will produce Rs. 630.50 as compound interest at 5% compounded annually.

Divide Rs. 28,730 between A and B so that when their shares are lent out at 10% compound interest compounded per year, the amount that A receives in 3 years is the same as what B receives in 5 years.

A sum of Rs 44,200 is divided between John and Smith, 12 years and 14 years old respectively, in such a way that if their portions be invested at 10% per annum compound interest, they will receive equal amounts on reaching 16 years of age.
(i) What is the share of each out of Rs44,200 ?
(ii) What will each receive, when 16years old ?

The simple interest on a certain sum of money and at 10% per annum is Rs. 6,000 in 2 years, Find:

1. the sum.
2. the amount due to the end of 3 years and at the same rate of interest compounded annually.
3. the compound interest earned in 3 years. 

Find the difference between compound interest and simple interest on Rs. 8,000 in 2 years and at 5% per annum.

Find the cube of : 3a- 2b

Find the cube of : 5a + 3b

Find the cube of : `2a + 1/(2a)`     ( a ≠ 0 )

Find the cube of: `( 3a - 1/a )  (a ≠ 0 )`

If  a² + `1/a^2 = 47` and a ≠ 0   find :

1. `a + 1/a`
2. `a^3 + 1/a^3`

If  `a^2 + 1/a^2` = 18; a ≠ 0 find :

(i) `a - 1/a`

(ii) `a^3 - 1/a^3`

If `a + 1/a` = p and a ≠ 0; then show that:

`a^3 + 1/a^3 = p(p^2 - 3)` 

If a + 2b = 5; then show that : a³ + 8b³ + 30ab = 125.