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Find the value of k in each of the following:
`(root(3)(8))^((-1)/(2)` = 2k
Concept: undefined >> undefined
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk
Concept: undefined >> undefined
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Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
Concept: undefined >> undefined
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
Concept: undefined >> undefined
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
Concept: undefined >> undefined
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
Concept: undefined >> undefined
If `root(x)("a") = root(y)("b") = root(z)("c")` and abc = 1, prove that x + y + z = 0
Concept: undefined >> undefined
If ax = by = cz and b2 = ac, prove that y = `(2xz)/(z + x)`
Concept: undefined >> undefined
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
Concept: undefined >> undefined
Find the value of (8p)p if 9p + 2 - 9p = 240.
Concept: undefined >> undefined
If ax = by = cz and abc = 1, show that
`(1)/x + (1)/y + (1)/z` = 0.
Concept: undefined >> undefined
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
Concept: undefined >> undefined
If 2250 = 2a. 3b. 5c, find a, b and c. Hence, calculate the value of 3a x 2-b x 5-c.
Concept: undefined >> undefined
If 2400 = 2x x 3y x 5z, find the numerical value of x, y, z. Find the value of 2-x x 3y x 5z as fraction.
Concept: undefined >> undefined
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
Concept: undefined >> undefined
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
Concept: undefined >> undefined
Find the value of 'a' and 'b' if:
`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0
Concept: undefined >> undefined
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
Concept: undefined >> undefined
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
Concept: undefined >> undefined
Prove the following:
`("a"^"m"/"a"^"n")^("m"+"n"+1) ·("a"^"n"/"a"^1)^("n" + 1-"m").("a"^1/"a"^"m")^(1+"m"-"n")`
Concept: undefined >> undefined
