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Science (English Medium) इयत्ता ११ - CBSE Question Bank Solutions for Chemistry

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Chemistry
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Electronic configuration of some elements is given in Column I and their electron gain enthalpies are given in Column II. Match the electronic configuration with electron gain enthalpy.

Column (I) Column (II)
Electronic configuration Electron gain enthalpy/kJ mol–1
(i) 1s2 2s2 sp6 (A) – 53
(ii) 1s2 2s2 2p6 3s1 (B) – 328
(iii) 1s2 2s2 2p5 (C) – 141
(iv) 1s2 2s2 2p4 (D) + 48
[3] Classification of Elements and Periodicity in Properties
Chapter: [3] Classification of Elements and Periodicity in Properties
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Assertion (A): Boron has a smaller first ionisation enthalpy than beryllium.

Reason (R): The penetration of a 2s electron to the nucleus is more than the 2p electron hence 2p electron is more shielded by the inner core of electrons than the 2s electrons.

[3] Classification of Elements and Periodicity in Properties
Chapter: [3] Classification of Elements and Periodicity in Properties
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Assertion (A): Electron gain enthalpy becomes less negative as we go down a group.

Reason (R): Size of the atom increases on going down the group and the added electron would be farther from the nucleus.

[3] Classification of Elements and Periodicity in Properties
Chapter: [3] Classification of Elements and Periodicity in Properties
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Discuss the factors affecting electron gain enthalpy and the trend in its variation in the periodic table.

[3] Classification of Elements and Periodicity in Properties
Chapter: [3] Classification of Elements and Periodicity in Properties
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Stable form of A may be represented by the formula:

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Explain the non-linear shape of \[\ce{H2S}\] and non-planar shape of \[\ce{PCl3}\] using valence shell electron pair repulsion theory.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Elements \[\ce{X, Y}\] and \[\ce{Z}\] have 4, 5 and 7 valence electrons respectively. Write the molecular formula of the compounds formed by these elements individually with hydrogen.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Elements \[\ce{X, Y}\] and \[\ce{Z}\] have 4, 5 and 7 valence electrons respectively. Which of these compounds will have the highest dipole moment?

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Which of the following figures does not represent 1 mole of dioxygen gas at STP?

(i) 16 grams of gas

(ii) 22.7 litres of gas

(iii) 6.022 × 1023 dioxygen molecules

(iv) 11.2 litres of gas

[5] States of Matter:- Gases and Liquids
Chapter: [5] States of Matter:- Gases and Liquids
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What will be the molar volume of nitrogen and argon at 273.15 K and 1 atm?

[5] States of Matter:- Gases and Liquids
Chapter: [5] States of Matter:- Gases and Liquids
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\[\ce{PCl5, PCl3 and Cl2}\] are at equilibrium at 500 K in a closed container and their concentrations are 0.8 × 10–3 mol L–1, 1.2 × 10–3 mol L–1 and 1.2 × 10–3 mol L–1 respectively. The value of Kc for the reaction \[\ce{PCl5 (g) ⇌ PCl3 (g) + Cl2 (g)}\] will be ______.

[6] Equilibrium
Chapter: [6] Equilibrium
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\[\ce{pH}\] of a solution of a strong acid is 5.0. What will be the \[\ce{pH}\] of the solution obtained after diluting the given solution a 100 times?

[6] Equilibrium
Chapter: [6] Equilibrium
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Calculate the \[\ce{pH}\] of a solution formed by mixing equal volumes of two solutions A and B of a strong acid having \[\ce{pH}\] = 6 and \[\ce{pH}\] = 4 respectively.

[6] Equilibrium
Chapter: [6] Equilibrium
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Match the following graphical variation with their description

A B
(i)   (a) Variation in product concentration with time 
(ii)  (b) Reaction at equilibrium
(iii)  (c) Variation in reactant concentration with time
[6] Equilibrium
Chapter: [6] Equilibrium
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The oxide that gives \[\ce{H2O2}\] on treatment with dilute \[\ce{H2SO4}\] is ______.

[9] Hydrogen
Chapter: [9] Hydrogen
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When sodium peroxide is treated with dilute sulphuric acid, we get ______.

[9] Hydrogen
Chapter: [9] Hydrogen
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Which of the following ions will cause hardness in water sample?

[9] Hydrogen
Chapter: [9] Hydrogen
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Which of the following compounds is used for water softening?

[9] Hydrogen
Chapter: [9] Hydrogen
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Hardness of water may be temporary or permanent. Permanent hardness is due to the presence of:

(i) Chlorides of \[\ce{Ca}\] and \[\ce{Mg}\] in water.

(ii) Sulphates of \[\ce{Ca}\] and \[\ce{Mg}\] in water.

(iii) Hydrogen carbonates of \[\ce{Ca}\] and \[\ce{Mg}\] in water.

(iv) Carbonates of alkali metals in water.

[9] Hydrogen
Chapter: [9] Hydrogen
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Complete the following equations:

\[\ce{PbS (s) + H2O2 (aq) ->}\]

[9] Hydrogen
Chapter: [9] Hydrogen
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