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Find the shortest distance between the following pairs of lines whose vector are: \[\overrightarrow{r} = \left( \hat{i} + \hat{j} \right) + \lambda\left( 2 \hat{i} - \hat{j} + \hat{k} \right) \text{ and } , \overrightarrow{r} = 2 \hat{i} + \hat{j} - \hat{k} + \mu\left( 3 \hat{i} - 5 \hat{j} + 2 \hat{k} \right)\]

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the angle between the lines 

\[\vec{r} = \left( 2 \hat{i}  - 5 \hat{j}  + \hat{k}  \right) + \lambda\left( 3 \hat{i}  + 2 \hat{j}  + 6 \hat{k}  \right)\] and \[\vec{r} = 7 \hat{i} - 6 \hat{k}  + \mu\left( \hat{i}  + 2 \hat{j}  + 2 \hat{k}  \right)\] 

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Write the equation of a plane which is at a distance of \[5\sqrt{3}\] units from origin and the normal to which is equally inclined to coordinate axes.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the equation of the plane which contains the line of intersection of the planes \[x + 2y + 3z - 4 = 0 \text { and } 2x + y - z + 5 = 0\] and whose x-intercept is twice its z-intercept.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane in Normal Form

Find the equation of a plane which passes through the point (3, 2, 0) and contains the line \[\frac{x - 3}{1} = \frac{y - 6}{5} = \frac{z - 4}{4}\].

 
Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the distance of the point (1, −2, 3) from the plane x − y + z = 5 measured parallel to the line whose direction cosines are proportional to 2, 3, −6.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Show that the lines \[\frac{5 - x}{- 4} = \frac{y - 7}{4} = \frac{z + 3}{- 5} \text { and } \frac{x - 8}{7} = \frac{2y - 8}{2} = \frac{z - 5}{3}\] are coplanar.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the distance of the point P(3, 4, 4) from the point, where the line joining the points A(3, –4, –5) and B(2, –3, 1) intersects the plane 2x + y + z = 7.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Plane Passing Through the Intersection of Two Given Planes

Find the equation of the plane that contains the point (1, –1, 2) and is perpendicular to both the planes 2x + 3y – 2z = 5 and x + 2y – 3z = 8. Hence, find the distance of point P (–2, 5, 5) from the plane obtained

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

Find the distance of the point P (–1, –5, –10) from the point of intersection of the line joining the points A (2, –1, 2) and B (5, 3, 4) with the plane x – y + z = 5.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

If a plane passes through the point (1, 1, 1) and is perpendicular to the line \[\frac{x - 1}{3} = \frac{y - 1}{0} = \frac{z - 1}{4}\] then its perpendicular distance from the origin is ______.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the vector equation of the plane with intercepts 3, –4 and 2 on x, y and z-axis respectively.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

Find the direction cosines of the line joining the points P(4,3,-5) and Q(-2,1,-8) . 

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Direction Cosines and Direction Ratios of a Line

Find the value of p for which the following lines are perpendicular : 

`(1-x)/3 = (2y-14)/(2p) = (z-3)/2 ; (1-x)/(3p) = (y-5)/1 = (6-z)/5`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the value of  λ for which the following lines are perpendicular to each other: 

`(x - 5)/(5 lambda + 2 ) = ( 2 - y )/5 = (1 - z ) /-1 ; x /1 = ( y + 1/2)/(2 lambda ) = ( z -1 ) / 3`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the vector and cartesian equations of the plane passing throuh the points (2,5,- 3), (-2, - 3,5) and (5,3,-3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (–1, –3, –1).

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the equation of the plane passing through the intersection of the planes `vec(r) .(hat(i) + hat(j) + hat(k)) = 1"and" vec(r) . (2 hat(i) + 3hat(j) - hat(k)) +4 = 0 `and parallel to x-axis. Hence, find the distance of the plane from x-axis.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the value of λ for which the following lines are perpendicular to each other `("x"-5)/(5λ+2) = (2 -"y")/(5) = (1 -"z")/(-1); ("x")/(1) = ("y"+1/2)/(2λ) = ("z" -1)/(3)`

hence, find whether the lines intersect or not

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

Find the equation of the plane passing through the intersection of the planes `vecr . (hati + hatj + hatk)` and `vecr.(2hati + 3hatj - hatk) + 4 = 0` and parallel to the x-axis. Hence, find the distance of the plane from the x-axis.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Plane Passing Through the Intersection of Two Given Planes

Find the vector and cartesian equation of the plane passing through the point (2, 5, - 3), (-2, -3, 5) and (5, 3, -3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (-1, -3, -1).

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane
< prev  761 to 780 of 831  next > 
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