HSC Commerce कक्षा १२ - Tamil Nadu Board of Secondary Education Question Bank Solutions for Business Mathematics and Statistics

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Value which is obtained by multiplying possible values of a random variable with a probability of occurrence and is equal to the weighted average is called

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Demand of products per day for three days are 21, 19, 22 units and their respective probabilities are 0.29, 0.40, 0.35. Profit per unit is 0.50 paisa then expected profits for three days are

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Probability which explains x is equal to or less than a particular value is classified as

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Given E(X) = 5 and E(Y) = – 2, then E(X – Y) is

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If X is a discrete random variable and p(x) is the probability of X, then the expected value of this random variable is equal to

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Which of the following is not possible in probability distribution?

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A discrete probability distribution may be represented by

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A probability density function may be represented by

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E[X – E(X)] is equal to

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E[X – E(X)]² is

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`int_(-oo)^oo` f(x) dx is always equal to

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A listing of all the outcomes of an experiment and the probability associated with each outcome is called

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If p(x) = `1/10`, x = 10, then E(X) is

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An expected value of a random variable is equal to it’s

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A discrete probability function p(x) is always non-negative and always lies between

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The distribution function F(x) is equal to

Prove that if E(X) = 0, then V(X) = E(X²)

What is the expected value of a game that works as follows: I flip a coin and if tails pay you ₹ 2; if heads pay you ₹ 1. In either case, I also pay you ₹ 0.50

Prove that V(aX) = a²V(X)

Prove that V(X + b) = V(X)