SSLC (English Medium) कक्षा १० - Tamil Nadu Board of Secondary Education Question Bank Solutions for Mathematics

If A, B, C are any three events such that probability of B is twice as that of probability of A and probability of C is thrice as that of probability of A and if P(A ∩ B) = `1/6`, P(B ∩ C) = `1/4`, P(A ∩ C) = `1/8`, P(A ∪ B ∪ C) = `9/10` and P(A ∩ B ∩ C) = `1/15`, then find P(A), P(B) and P(C)

In a class of 35, students are numbered from 1 to 35. The ratio of boys to girls is 4 : 3. The roll numbers of students begin with boys and end with girls. Find the probability that a student selected is either a boy with prime roll number or a girl with composite roll number or an even roll number.

If two dice are rolled, then find the probability of getting the product of face value 6 or the difference of face values 5

In a two children family, find the probability that there is at least one girl in a family

The King, Queen and Jack of the suit spade are removed from a deck of 52 cards. One card is selected from the remaining cards. Find the probability of getting a diamond

The King, Queen and Jack of the suit spade are removed from a deck of 52 cards. One card is selected from the remaining cards. Find the probability of getting a queen

The King, Queen and Jack of the suit spade are removed from a deck of 52 cards. One card is selected from the remaining cards. Find the probability of getting a spade

The King, Queen and Jack of the suit spade are removed from a deck of 52 cards. One card is selected from the remaining cards. Find the probability of getting a heart card bearing the number 5

Show that the angle bisectors of a triangle are concurrent

An artist has created a triangular stained glass window and has one strip of small length left before completing the window. She needs to figure out the length of left out portion based on the lengths of the other sides as shown in the figure

O is any point inside a triangle ABC. The bisector of ∠AOB, ∠BOC and ∠COA meet the sides AB, BC and CA in point D, E and F respectively. Show that AD × BE × CF = DB × EC × FA

Let ABC be a triangle and D, E, F are points on the respective sides AB, BC, AC or their extensions. Let AD : DB = 5 : 3, BE : EC = 3 : 2 and AC = 21 . Find the length of the line segment CF

If the function f is defined by f(x) = `{{:(x + 2";", x > 1),(2";", -1 ≤ x ≤ 1),(x - 1";", -3 < x < -1):}` find the value of f(3)

If the function f is defined by f(x) = `{{:(x + 2";", x > 1),(2";", -1 ≤ x ≤ 1),(x - 1";", -3 < x < -1):}` find the value of f(0)

If the function f is defined by f(x) = `{{:(x + 2";", x > 1),(2";", -1 ≤ x ≤ 1),(x - 1";", -3 < x < -1):}` find the value of f(− 1.5)

If the function f is defined by f(x) = `{{:(x + 2";", x > 1),(2";", -1 ≤ x ≤ 1),(x - 1";", -3 < x < -1):}` find the value of f(2) + f(– 2)

A function f: [– 5, 9] → R is defined as follow :

f(x) = `{{:(6x + 1";", -5 ≤ x < 2),(5x^2 - 1";", 2 ≤ x < 6),(3x - 4";", 6 ≤ x ≤ 9):}` Find f(– 3) + f(2)

A function f: [– 5, 9] → R is defined as follow :

f(x) = `{{:(6x + 1";", -5 ≤ x < 2),(5x^2 - 1";", 2 ≤ x < 6),(3x - 4";", 6 ≤ x ≤ 9):}` Find f(7) – f(1)

A function f: [– 5, 9] → R is defined as follow :

f(x) = `{{:(6x + 1";", -5 ≤ x < 2),(5x^2 - 1";", 2 ≤ x < 6),(3x - 4";", 6 ≤ x ≤ 9):}` Find 2f(4) + f(8)

A function f: [– 5, 9] → R is defined as follow :

f(x) = `{{:(6x + 1";", -5 ≤ x < 2),(5x^2 - 1";", 2 ≤ x < 6),(3x - 4";", 6 ≤ x ≤ 9):}` Find `(2"f"(- 2) - "f"(6))/("f"(4) + "f"( -2))`