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HSC Arts (English Medium) ११ वीं कक्षा - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
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Prove the following identity:

1 + 3cosec2θ cot2θ + cot6θ = cosec6θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

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Select the correct option from the given alternatives: 

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Select the correct option from the given alternatives:

If θ = 60°, then `(1 + tan^2theta)/(2tantheta)` is equal to

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Select the correct option from the given alternatives:

If cosecθ + cotθ = `5/2`, then the value of tanθ is

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Select the correct option from the given alternatives:

If cosecθ − cotθ = q, then the value of cot θ is

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

2 sec2θ – sec4θ – 2cosec2θ + cosec4θ = cot4θ – tan4θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

sin4θ + cos4θ = 1 – 2 sin2θ cos2θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

cos4θ − sin4θ +1= 2cos2θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

sin4θ +2sin2θ . cos2θ = 1 − cos4θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

tan2θ − sin2θ = sin4θ sec2θ

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined

Prove the following:

sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)

[1.2] Trigonometry - 1
Chapter: [1.2] Trigonometry - 1
Concept: undefined >> undefined
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