Science (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Mathematics

Any tangent to the curve y = 2x⁷ + 3x + 5 __________________ .

The point on the curve 9y² = x³, where the normal to the curve makes equal intercepts with the axes is

(a) \[\left( 4, \frac{8}{3} \right)\]

(b) \[\left( - 4, \frac{8}{3} \right)\]

(c) \[\left( 4, - \frac{8}{3} \right)\]

(d) none of these

The slope of the tangent to the curve x = t² + 3t − 8, y = 2t² − 2t − 5 at the point (2, −1) is _____________ .

The line y = mx + 1 is a tangent to the curve y² = 4x, if the value of m is ________________ .

The normal at the point (1, 1) on the curve 2y + x² = 3 is _____________ .

The normal to the curve x² = 4y passing through (1, 2) is _____________ .

Form the differential equation representing the family of curves y = mx, where m is an arbitrary constant.

Form the differential equation of the family of ellipses having foci on y-axis and centre at the origin.

Form the differential equation of the family of hyperbolas having foci on x-axis and centre at the origin.

Form the differential equation representing the family of curves `y² = m(a² - x²) by eliminating the arbitrary constants 'm' and 'a'. 

Find the equation of a tangent and the normal to the curve `"y" = (("x" - 7))/(("x"-2)("x"-3)` at the point where it cuts the x-axis

Find the area of the region bounded by the curves (x -1)² + y² = 1 and x² + y² = 1, using integration.

Form the differential equation representing the family of curves y = e²x (a + bx), where 'a' and 'b' are arbitrary constants.

Find the equation of the tangent line to the curve `"y" = sqrt(5"x" -3) -5`, which is parallel to the line  `4"x" - 2"y" + 5 = 0`.

Form the differential equation representing the family of curves y = A sin x, by eliminating the arbitrary constant A.

Find the equation of tangent to the curve `y = sqrt(3x -2)` which is parallel to the line 4x − 2y + 5 = 0. Also, write the equation of normal to the curve at the point of contact.

x = `"t" + 1/"t"`, y = `"t" - 1/"t"`

x = `"e"^theta (theta + 1/theta)`, y= `"e"^-theta (theta - 1/theta)`

x = 3cosθ – 2cos³θ, y = 3sinθ – 2sin³θ

sin x = `(2"t")/(1 + "t"^2)`, tan y = `(2"t")/(1 - "t"^2)`