1. Inform you about time table of exam.
2. Inform you about new question papers.
3. New video tutorials information.
- Quadratic Equation part 6 (Example: Factorization)
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- Quadratic Equation part 5 (Solution by Factorization)
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- Solution by Factorising
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- Solution by Factorising (Exercise)
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- Quadratic equation solution through Factorisation
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- Find the roots of the Quadratic Equation by Factorisation Example
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- Methods of Solving Quadratic Equation.
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The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with
A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750. We would like to find out the number of toys produced on that day.
A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced and the cost of each article.
Solve the following quadratic equations
(i) 7x2 = 8 – 10x
(ii) 3(x2 – 4) = 5x
(iii) x(x + 1) + (x + 2) (x + 3) = 42
The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is `29/20`. Find the original fraction.