- K.E. and P.E. in S.H.M
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Calculate the average molecular kinetic energy :
(a) per kilomole, (b) per kilogram, of oxygen at 27°C.
(R = 8320 J/k mole K, Avogadro's number = 6*03 x 1026 molecules/K mole)
If the frequency of incident light falling on a photosensitive material is doubled, then the kinetic energy of the emitted photoelectron will‘be........................................
- same as its initial value
- two times its initial value
- more than two times its initial value
- less than two times its initial value
Prove the law of conservation of energy for a particle performing simple harmonic motion.Hence graphically show the variation of kinetic energy and potential energy w. r. t.instantaneous displacement.
Derive an expression for kinetic energy, when a rigid body is rolling on a horizontal surface without slipping.Hence tind kinetic energy for a solid sphere.
The kinetic energy of nitrogen per unit mass at 300 K is 2.5 × 106 J/kg. Find the kinetic energy of 4 kg oxygen at 600 K. (Molecular weight of nitrogen = 28, Molecular weight of oxygen = 32)
State an expression for K. E. (kinetic energy) and P. E. (potential energy) at displacement ‘x’ for a particle performing linear S.H. M. Represent them graphically. Find the displacement at which K. E. is equal to P. E.