In the give figure, ABC is a triangle with ∠EDB = ∠ACB. Prove that ΔABC ~ ΔEBD. If BE =6 cm, EC = 4cm, BD = 5cm and area of ΔBED = 9 cm2. Calculate the:
(i) length of AB]
(ii) area of Δ ABC
The ratio between the areas of two similar triangles is 16 : 25, Find the ratio between their:
(i) perimeters (ii) altitudes (iii) medians
The ratio between the altitudes of two similar triangles is 3 : 5; write the ratio between their:
(i) medians (ii) perimeters (iii) areas
In the given figure, ABC is a triangle. DE is parallel to BC and `(AD)/(DB)=3/2`
(1) Determine the ratios `(AD)/(AB) and (DE)/(BC)`
(2 ) Prove that ∆DEF is similar to ∆CBF Hence, find `(EF)/(FB)`.
(3) What is the ratio of the areas of ∆DEF and ∆BFC.
In the given figure, ∠B = ∠E, ∠ACD = ∠BCE, AB = 10.4cm and DE = 7.8 cm. Find the ratio
between areas of the ∆ABC and ∆ DEC
Two isosceles triangles have equal vertical angles. Show that the triangles are similar.If the ratio between the areas of these two triangles is 16 : 25, find the ratio between their corresponding altitudes.
In ΔABC, AP : PB = 2 : 3. PO is parallel to BC and is extended to Q so that CQ is parallel to BA.
(i) area ΔAPO : area Δ ABC.
(ii) area ΔAPO : area Δ CQO.