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Acute Angle Between the Lines represented by ax2+2hxy+by2=0
- Acute angle between the lines
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Show that the equation `x^2-6xy+5y^2+10x-14y+9=0 ` represents a pair of lines. Find the acute angle between them. Also find the point of intersection of the lines.
If θ is the acute angle between the lines represented by equation ax2 + 2hxy + by2 = 0 then prove that `tantheta=|(2sqrt(h^2-ab))/(a+b)|, a+b!=0`
If θ is the measure of acute angle between the pair of lines given by `ax^2+2hxy+by^2=0,` then prove that `tantheta=|(2sqrt(h^2-ab))/(a+b)|,a+bne0`
Find ‘k' if the sum of slopes of lines represented by equation x2+ kxy - 3y2 = 0 is twice their product.
The slopes of the lines given by 12x2 + bxy + y2 = 0 differ by 7. Then the value of b is :
(B) ± 2
(C) ± 1