#### notes

find the sum of first n terms of some special series,

i) 1 + 2 + 3 +… + n (sum of first n natural numbers)

ii) `1^2 + 2^2 + 3^2 +… + n^2`(sum of squares of the first n natural numbers)

Let us take them one by one.

i) `S_n=1 + 2 + 3 + … + n`, then `S_n = n(n+1)/2`

ii) `S_n =1^2 + 2^2 + 3^2 +… + n^2`

then = `(n(n+1)(2n+1))/6`

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