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**For example :** Arjun is twice as old as Shriya. Five years ago his age was three times Shriya’s age. Find their present ages. **Solution:**

Let us take Shriya’s present age to be x years.

Then Arjun’s present age would be 2x years.

Shriya’s age five years ago was (x – 5) years.

Arjun’s age five years ago was (2x – 5) years.

It is given that Arjun’s age five years ago was three times Shriya’s age.

Thus, 2x – 5 = 3(x – 5)

or 2x – 5 = 3x – 15

or 15 – 5 = 3x – 2x

or 10 = x

So, Shriya’s present age = x = 10 years.

Therefore, Arjun’s present age = 2x = 2 × 10 = 20 years.