SSC (English Medium) Class 10th Board ExamMaharashtra State Board
Share
Notifications

View all notifications

Roots of a Quadratic Equation

Login
Create free account


      Forgot password?

notes

In the previous class you have studied that if value of the polynomial is zero for
x = a then (x - a) is a factor of that polynomial. That is if p(x) is a polynomial and p(a) = 0 then (x - a) is a factor of p(x). In this case ’a’ is the root or solution of p(x) = 0
For Example 

Let x = -6 in the polynomial x2 + 5x - 6
     x2 + 5x - 6 = (-6)2 + 5 × (-6) - 6
    = 36 - 30 - 6 = 0
∴x= -6 is a solution of the equation.
Hence -6 is one root of the equation
    x2 + 5x - 6 = 0

Let x = 2 in polynomial x2 + 5x - 6
   x2 + 5x - 6 = 22 + 5×2 - 6
   = 4 + 10 - 6
   = 8 ¹ 0
∴ x = 2 is not a solution of the
equation x2 + 5x - 6 = 0

S
View in app×