#### notes

In this multiplication, we shall have to multiply each of the three terms in the trinomial by each of the two terms in the binomial.

For instance ,

`(a + 7) xx (a^2 + 3a + 5)`

= `a xx (a^2 + 3a + 5) xx 7 xx (a^2 + 3a + 5)` .... [using the distributive law]

= `a^3 + 3a^2 + 5a + 7a^2 + 21a + 35`

= `a^3 + (3a^2 + 7a^2) + (5a + 21a) + 35`

= `a^3 + 10a^2 + 26a + 35`