#### notes

Observe the following examples.

(i) `4xy × 5x^2y^2 × 6x^3y^3` = `(4xy × 5x^2y^2) × 6x^3y^3`

`= 20x^3y^3 × 6x^3y^3 = 120x^3y^3 × x^3y^3`

`= 120 (x^3 × x^3) × (y^3 × y^3) = 120x^6 × y^6`

`= 120x^6y^6`

It is clear that we first multiply the first two monomials and then multiply the resulting monomial by the third monomial. This method can be extended to the product of any number of monomials.