Shaalaa.com | Loci Part 1
Given: PQ is perpendicular bisector of side AB of the triangle ABC.
Prove: Q is equidistant from A and B.
The locus of the centres of a given circle which rolls around the outside of a second circle and is always touching it.
The locus of the centres of all circles that are tangent to both the arms of a given angle.
Given: AX bisects angle BAC and PQ is perpendicular bisector of AC which meets AX at point Y.
Prove: (i) X is equidistant from AB and AC.
(ii) Y is equidistant from A and C.
Construct a triangle ABC in which angle ABC = 75°, AB= 5cm and BC =6.4cm. Draw perpendicular bisector of side BC and also the bisector of angle ACB. If these bisectors intersect each other at point P; prove that P is equidistant from B and C; and also from AC and BC.