The triangle is right angled, we can directly apply the formula by using two sides containing the right angle as base and height.
|Area of a triangle = `1/2 xx base xx height`|
For example :
suppose that the sides of a right triangle ABC are 5 cm, 12 cm and 13 cm; we take base as 12 cm and height as 5 cm in following fig.
Then the area of ∆ ABC is given by
`1/2 xx base xx height`
= `1/2 xx 12 xx 5 cm^2`, i.e., 30 `"cm"^2`.
The perimeter of a triangular field is 540 m and its sides are in the ratio 25 : 17 : 12. Find the area of the triangle ?
In a ΔABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find the area of ΔABC and hence its altitude on AC ?