Advertisement Remove all ads

Converse of Basic Proportionality Theorem

Advertisement Remove all ads



Theorem : If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.

In figure 1.18, line l interesects the side AB and side AC of D ABC in the points P and Q respectively and `(AP)/(PB)
= (AQ)/(QC)`, hence line l || seg BC.

This theorem can be proved by indirect method. 

If you would like to contribute notes or other learning material, please submit them using the button below.
Advertisement Remove all ads

View all notifications

      Forgot password?
View in app×