In ΔABC, ∠ABC = ∠DAC. AB = 8 cm, AC = 4 cm, AD = 5 cm.
(i) Prove that ΔACD is similar to ΔBCA.
(ii) Find BC and CD.
(iii) Find area of ΔACD: area of ΔABC.
PQR is a triangle. S is a point on the side QR of ΔPQR such that `angle PSR = angle QPR`. Given QP = 8 cm,PR = 6 cm and SR = 3 cm.
1) Prove ΔPQR ~ ΔSPR
2) Find the length of QR and PS
3) `" area of ΔPQR"/"area of ΔSPR"`
Triangle ABC is an isosceles triangle in which AB = AC = 13 cm and BC = 10 cm. AD is
perpendicular to BC. If CE = 8 cm and EF ⊥ AB, find:
i)`"area of ADC"/"area of FEB"` ii)`"area of ΔAFEB"/"area of ΔABC"`
Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn
intersecting diagonal AC in L and AD produced in E. Prove that: EL = 2 BL.
An aeroplane is 30 m long and its model is 15 cm long. If the total outer surface area of the model is 150 cm2, find the cost of painting the outer surface of the aeroplane at the rate of Rs.120 per sq. m. Given that 50 sq. m of the surface of the aeroplane is left for windows.